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Direct Variation Question 2 with Solutions

Last week, I went over direct variation, and I gave you three direct variation problems to try on your own. You can see that post here: Direct Variation

Today I would like to give a solution to the second of those three problems. You can see solutions to the first problem here: Direct Variation Q1.

Example: The amount of revenue that an online magazine retailer makes in a month is directly proportional to the number of active subscribers to the magazine. In July, the magazine had a total of 1200 subscribers, and the retailer reported revenue of $7200. In August, the online magazine had a total of 1500 subscribers. How much revenue did the retailer make?

Try to solve the problem yourself before checking the solutions below.

Solutions

(1) Since the revenue, R, is directly proportional to the number of subscribers, x, R = kx for some constant k. We are given that = 7200 when = 1200, so that 7200 = k(1200), or = 7200/1200 = 6. Thus, y = 6x. When = 1500, we have = 6 ⋅ 1500 = 9000.

(2) Since R is directly proportional to x,  R/x  is a constant. So we get the following ratio:  7200/1200 = R/1500. Cross multiplying gives 1200= 7200 ⋅ 1500, or equivalently, R = (7200⋅1500)/1200 = 9000.

(3) The graph of = f(x) is a line passing through the points (0, 0) and (1200, 7200). The slope of this line is  (7200 – 0)/(1200 – 0) = 6. Writing the equation of the line in slope-intercept form we have y = 6x. As in solution 1, when = 1500, we have = 6 ⋅ 1500 = 9000.

 

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