Inverse Variation Question 2 with Solution Last week, I went over inverse variation, and I gave you four inverse variation problems to try on your own. You can see that post here: Inverse Variation Today I would like to give a solution to the second of those four problems. You can see a solution to the first problem here: Inverse Variation Q1 Example: If x varies inversely as y2, and x is 3 when y is 5, then what is x when y is 3 ? Try to solve the problem yourself before checking the solution below. Solution: We are given that y = 5 when x = 3. Since x varies inversely as y2, we have that xy2 is a constant. So we get the following equation: (3)(25) = x(9). So 75 = 9x, and therefore x = 75/9 = 25/3. More Problems with Explanations If you are preparing for the SAT, ACT, or an SAT math subject test, you may want to take a look at the Get 800 collection of test prep books. And if you liked this article, please share it with your Facebook friends: Comments comments