500 New SAT Math Problems
Just 19.99 on Amazon
Hi everyone! The latest edition of 500 New SAT Math Problems is now available in paperback from Amazon. This edition just has been modified from the previous edition to account for the changes on the Digital SAT.
The paperback is now on sale on Amazon for only $19.99. Note that once the sale ends (by the end of today), the price of this book will go up to $42.99.
The promotion has ended. Thanks to everyone who participated. The book is now available at its regular price here: 500 New SAT Math Problems
If you have any questions, feel free to contact me at steve@SATPrepGet800.com
Thank you all for your continued support!
A Trick For Free Two Day Shipping
I would like to finish this post with a little trick you can use to get free 2 day shipping on any of the books you decide to purchase without making any additional purchases. If you have never used Amazon Prime you can sign up for a free month using the following link.
Sign Up For Amazon Prime For Free
If you have already had a free trial of Amazon Prime you can simply open up a new Amazon account to get a new free trial. It just takes a few minutes! You will need to use a different email address than the one you usually use.
This next part is very important! After you finish your transaction, go to your Account, select “Manage my prime membership,” and turn off the recurring billing. This way in a month’s time Amazon will not start charging you for the service.
After shutting off the recurring billing you will still continue to receive the benefit of free 2 day shipping for one month. This means that as long as you use this new Amazon account for your purchases you can do all of your shopping on Amazon for the next month without having to worry about placing minimum orders to get free shipping.
Just be aware that certain products from outside sellers do not always qualify for free shipping, so please always check over your bill carefully before you check out.
Well I hope you decide to take advantage of this very special offer, or at the very least I hope you will benefit from my Amazon “free 2 day shipping trick.” Here is the link one more time:
Sign Up For Amazon Prime For Free
If you think your friends might be interested in this special offer, please share it with them on Facebook:
Thank you all for your continued support!
New SAT Verbal Prep Book
Today I would like to announce the release of the New SAT Verbal Prep Book for Reading and Writing Mastery.
The paperback is now on sale on Amazon for only $4.22. This sale may run for just a few hours (until 12 PM), and once the sale ends the price will go up to $34.99. If you want to take advantage of the sale price I strongly recommend you purchase the book right away.
The sale is over. But I will still honor the other promotions listed below.
Click the following link to get to the book’s Amazon page: New SAT Verbal Prep Book
Note that this book is for the revised SAT beginning March, 2016.
As an additional incentive to purchase this book today, I will also give you another book for FREE as a downloadable PDF file. You can choose ANY of my other books. So if you would like a different book, go ahead and purchase this one (as soon as it is available), forward me your Amazon confirmation email and let me know which of my books you would like for free. You will be provided with a link to download your additional free book. This offer is available until the end of today (June 4, 2015).
Take a look at my product page to see all of my books: Get 800 Product Page
I am also making the following promotion available until June 30, 2015: if you buy any 3 of my books in paperback, you get all 6 of the following SAT math prep books for free.
Additionally, you will receive New SAT Math Problems which consists of 240 math problems and full explanations for the Revised SAT.
A Trick For Free Two Day Shipping
I would like to finish this post with a little trick you can use to get free 2 day shipping on any of the books you decide to purchase without making any additional purchases. If you have never used Amazon Prime you can sign up for a free month using the following link.
Sign Up For Amazon Prime For Free
If you have already had a free trial of Amazon Prime you can simply open up a new Amazon account to get a new free trial. It just takes a few minutes! You will need to use a different email address than the one you usually use.
This next part is very important! After you finish your transaction, go to your Account, select “Manage my prime membership,” and turn off the recurring billing. This way in a month’s time Amazon will not start charging you for the service.
After shutting off the recurring billing you will still continue to receive the benefit of free 2 day shipping for one month. This means that as long as you use this new Amazon account for your purchases you can do all of your shopping on Amazon for the next month without having to worry about placing minimum orders to get free shipping.
Just be aware that certain products from outside sellers do not always qualify for free shipping, so please always check over your bill carefully before you check out.
Well I hope you decide to take advantage of this very special offer, or at the very least I hope you will benefit from my Amazon “free 2 day shipping trick.” Here is the link one more time:
Sign Up For Amazon Prime For Free
If you think your friends might be interested in this special offer, please share it with them on Facebook:
Thank you all for your continued support!
New SAT Verbal Prep Book for Reading and Writing Mastery
Today I am happy to announce that the New SAT Verbal Prep Book for Reading and Writing Mastery will be available this week. This book will prepare you for the revised SAT beginning March, 2016 (as well as the PSAT being administered in October, 2015).
This book will be released on Amazon at a promotional price of about $4.00 for a few hours.
Once the sale ends the price will go up to $34.99. If you want to take advantage of the sale price I strongly recommend that you get on the notification list.
If you want to be added to my email notification list for this and future promotions, send an email to steve@SATPrepGet800.com with “Notify me” written in the subject line.
In the meantime, you can take a look at my product page to see all of the other books from the Get 800 collection: Get 800 Product Page
If you think your friends might be interested in this special offer, please share it with them on Facebook:
Thank you all for your continued support!
Hello everyone.
Today I have uploaded a video to my YouTube channel on the Distributive Property and Factoring
For your convenience I have also embedded this video below:
If you liked this video, please share it with your Facebook friends:
Hello everyone.
I have already taught you a nice method for multiplying polynomials in a previous blog post. The original article is here: Multiplying Polynomials
Today I have also uploaded this information as a video on my YouTube channel. You can visit the YouTube page here: Multiplying Polynomials
For your convenience I have also embedded this video below:
If you liked this video, please share it with your Facebook friends:
And if you are preparing for a standardized test, you may want to take a look at the following books:
Until next time…
Free Proctored Exam
Sullivan Tutorials, in cooperation with Get 800, are inviting you to Staten Island, NY to take a free proctored PSAT. The test will be available on
May 14th from 7:00 – 9:30 P.M OR May 17th from 9:30 A.M. – 12:00 P.M.
We will be testing students to see if they can make it into one our National Merit prep groups. There is no charge to take this proctored test and there is no obligation to sign up for a course. To save yourself a seat, please register by entering your email address in the box below:
You will receive the testing location via email.
About Sullivan Tutorials
For the past 25 years, Sullivan Tutorials has been responsible for about 60% of all the National Merit Semi-Finalists and all but a few of the Finalists on Staten Island. Students are placed in groups of 5-6 students with similar math scores. Groups meet for math sessions in the home of one student and for verbal sessions in the home of another student in the group.
National Merit Students
Students that make it into one of the National Merit groups will start meeting on weekday evenings in mid-July. They will meet for two 3 hour verbal sessions and two 2 hour math sessions in July and August and then 2 hour sessions once a week right up to the PSAT in October. They will then take the PSAT in October, and the SAT in Nov, Dec and Jan.
This is a very difficult year as the SAT is radically changing. To see some of the major changes, take a look at this article I wrote last week: Preview the Math Changes on the “New” SAT
In addition, here are some of the changes in SAT Verbal:
- The essay will be optional – individual institutions will decide if they require the essay.
- There will be a 65 minute reading section.
- There will be a 35 minute language and writing section.
- There will no longer be sentence completions.
- There will be a greater emphasis on the meaning of words in extended contexts, and on how word choice shapes meaning, tone and impact.
National Merit students will be prepared primarily for the old SAT with some intensive work for the new one right before the PSAT.
Other Students
Students who do not make into one of the National Merit groups may start preparing with Sullivan Tutorials in mid-August to take the November, December and January exams if they are fairly strong in math and have scores that are reasonably high. All other students will begin preparing in January and take the new May exam.
Meetings in May will start with a 15 minute Q & A for parents and then students will take a 2 hour and ten minute PSAT. These exams will be graded before the students leave. Parents can either have a consultation right then, or they can do so by phone during the week after the exam.
National Merit Information
There are three levels for the National Merit. The first is 201 pts and up which is Commended Student. This information goes to any two colleges that the student designates. The second and more important level is Semi-Finalist. The cut off for this varies between 215 and 219 in New York State. 218 is the most common number. Students who get this are considered elite – most colleges want these students for bragging rights. These students are informed in early September of their senior year that they are semi-finalists and they are given the opportunity to write an essay that is evaluated by a committee. The top 1000 students in America are then designated as Finalists. Scholarship money is attached to this designation. On the aegis of becoming a finalist, many students are eligible for full scholarships to some of their chosen schools.
Once again, to save yourself a seat for the proctored exam, simply enter your email in the box below:
And please contact me with any questions or concerns:
If you think some of your friends might be interested in this, please share:
New SAT Math Problems
Today I would like to announce the release of New SAT Math Problems arranged by Topic and Difficulty Level.
The paperback is now on sale on Amazon for only $4.49. The sale is over. Thanks to all who have participated. I will still honor the other promotions mentioned below.
This sale may run for just a few hours, and once the sale ends the price will go up to $34.99. If you want to take advantage of the sale price I strongly recommend you purchase the book right away.
Click the following link to get to the book’s Amazon page: New SAT Math Problems
Note that this book is for the revised SAT. For more details about these revisions take a look at the following article that I just wrote: Preview the Math Changes on the “New” SAT
As an additional incentive to purchase this book today, I will also give you another book for FREE as a downloadable PDF file. You can choose ANY of my other books. So if you would like a different book, go ahead and purchase this one (as soon as it is available), forward me your Amazon confirmation email and let me know which of my books you would like for free. You will be provided with a link to download your additional free book. This offer is available until the end of today (April 27, 2015).
Take a look at my product page to see all of my books: Get 800 Product Page
I am also making the following promotion available until April 30, 2015: if you buy any 3 of my books in paperback, you get all 6 of the following SAT math prep books for free.
A Trick For Free Two Day Shipping
I would like to finish this post with a little trick you can use to get free 2 day shipping on any of the books you decide to purchase without making any additional purchases. If you have never used Amazon Prime you can sign up for a free month using the following link.
Sign Up For Amazon Prime For Free
If you have already had a free trial of Amazon Prime you can simply open up a new Amazon account to get a new free trial. It just takes a few minutes! You will need to use a different email address than the one you usually use.
This next part is very important! After you finish your transaction, go to your Account, select “Manage my prime membership,” and turn off the recurring billing. This way in a month’s time Amazon will not start charging you for the service.
After shutting off the recurring billing you will still continue to receive the benefit of free 2 day shipping for one month. This means that as long as you use this new Amazon account for your purchases you can do all of your shopping on Amazon for the next month without having to worry about placing minimum orders to get free shipping.
Just be aware that certain products from outside sellers do not always qualify for free shipping, so please always check over your bill carefully before you check out.
Well I hope you decide to take advantage of this very special offer, or at the very least I hope you will benefit from my Amazon “free 2 day shipping trick.” Here is the link one more time:
Sign Up For Amazon Prime For Free
If you think your friends might be interested in this special offer, please share it with them on Facebook:
Thank you all for your continued support!
Revised SAT Math Problems with Solutions – Part 2
Two weeks ago I gave you two math problems for the revised SAT. To see that post click the following link: SAT Math Problems for the Revised SAT
You can find a solution to the first problem here: SAT Math Problems and Solutions for the Revised SAT
Today I will solve the second problem.
Before I give the solution, I would just like to remind you that if you buy any of my SAT prep books for the current SAT, you will be given access to download the new problems and solutions I am creating for the revised SAT. See last week’s post for details. And if you have any questions about this, simplysend me an email:
You can find all of my books here: https://satprepget800.com/products/
As promised here is a solution to the second question I gave two weeks ago.
Level 2 Data Analysis
-
A puddle with an area of 500 cm2, is monitored by scientists for the number of paramecia present. The scientists are interested in two distinct species, let’s call them “species A” and “species B.” At time t = 0, the scientists measure and estimate the amount of species A and species B present in the puddle. They then proceed to measure and record the number of each species of paramecium present every hour for 12 days. The data for each species, were then fit by a smooth curve, as shown in the graph above. Which of the following is a correct statement about the data above?
(A) At time t = 0, the number of species B present is 150% greater than the number of species A present.(B) At time t = 0, the number of species A present is 75% less than the number of species B present.(C) For the first 3 days, the average growth rate of species B is higher than the average growth rate of species A.(D) The growth rate of both species A and species B decreases for the last 8 days.
The last 8 days correspond to times t = 4 through t = 12. During this time, the growth rate of both species is decreasing. So the answer is choice (D).
Notes: (1) 300 = 200 + 2(100), and therefore 300 is 200% greater than 100. This eliminates choice (A).
(2) We can also use the percent change formula
Here the original value is 100 and the change is 300 – 100 = 200. It follows that Percent Change = (200/100)*100 = 200%.
(3) To eliminate choice (B) we can use the percent change formula again with original value 300 and change 300 – 100 = 200:
.Percent Change = (200/300)*100 = 200/3 = 66 2/3%.
(4) We can compute the average growth rate over the interval from t = a to t = b, by computing the slope of the line passing through the points (a,f(a)) and (b,f(b)). That is, we would compute m =(f(b) – f(a))/(b – a).
For example, over the first 3 days, the average growth rate of species A is approximately (400 – 100)/(3 – 0) = 300/3 = 100 paramecia per day. The two points we used here were (0,100) and (3,400).
Similarly, over the first 3 days, the average growth rate of species B is approximately (350 – 300)/(3 – 0) = 50/3 = 16 2/3 paramecia per day. The two points we used here were (0,300) and (3,350).
This eliminates choice (C).
(5) It should be noted that we do not actually need to compute the growth rates to determine which growth rate is higher. We can simply look at the “steepness” of the two curves. An easy way to do this is to draw a “tangent line” to each curve at the point where we wishto examine the growth rate. Here is an example of such an analysis at t = 2:
Notice that the tangent line for species A rises faster than the tangent line for species B. This shows that species A is growing faster than species B at time t = 2.
(6) We can use a similar analysis as we did in note 5 to see that the growth rate is decreasing for each species between times t = 4 and t = 12. Here as an example of such an analysis for Species B:
Notice that the tangent line at time t = 4 is steeper then the tangent line at time t = 8. This suggests that the growth rate of species B is decreasing from t = 4 to t = 12.
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And don’t forget to check out my social media pages:
Revised SAT Math Problems with Solutions
Last week I supplied you with two math problems for the revised SAT. To see that post click the following link: SAT Math Problems for the Revised SAT
Today I will solve the first of those two problems, and I will solve the second one next week.
Before I give the solution, I would just like to remind you that if you buy any of my SAT prep books for the current SAT, you will be given access to download the new problems and solutions I am creating for the revised SAT. See last week’s post for details. And if you have any questions about this, simplysend me an email:
You can find all of my books here: https://satprepget800.com/products/
As promised here is a solution to the first question I gave you last week.
Level 2 Number Theory
-
A chemist has a supply of 5.2 liter bottles of a certain solvent that must be shipped to a central warehouse. The warehouse can accept the solvent at the rate of 3 hectoliters per minute for a maximum of 8 hours per day. If 1 hectoliter equals 100 liters, what is the maximum number of bottles that the warehouse could receive from the chemist each day.
(A) 461(B) 462(C) 27,692(D) 83,200
The warehouse can receive 3 ∙ 60 ∙ 8 hectoliters of the solvent per day, or equivalently, 1440 ∙ 100 = 144,000 liters of the solvent per day. Therefore the number of bottles that can be accepted each day is 144,000/5.2 which is approximately 27,692.30769. The maximum number of bottles that the warehouse can accept in one day is therefore 27,692, choice (C).
Notes: (1) Since there are 60 minutes in an hour, “3 hectoliters per minute” is the same as 3 ∙ 60 = 180 hectoliters per hour.
Similarly, since the warehouse can accept the solvent for a maximum of 8 hours per day, “180 hectoliters per hour” is equivalent to a maximum of 180 ∙ 8 = 1440 hectoliters per day.
(2) In the above solution we combined the two conversions given in note 1 into a single conversion: “3 hectoliters per minute” is equivalent to a maximum of 3 ∙ 60 ∙ 8 = 1440 hectoliters per day.
(3) Since 1 hectoliter equals 100 liters, we can convert hectoliters to liters by multiplying by 100. So
1440 hectoliters is equal to 1440 ∙ 100 = 144,000 liters.
(4) We can convert between hectoliters and liters more formally by setting up a ratio. The two things being compared are “liters” and “hectoliters.”
liters 100 x
hectoliters 1 1440
Now draw in the division symbols and equal sign, cross multiply and divide the corresponding ratio to find the unknown quantity x.
100/1 = x/1440
1x = 100 ∙ 1440
x = 144,000
(5) Instead of converting 1440 hectoliters to 144,000 liters, and then dividing by 5.2, we can instead convert 5.2 liters to hectoliters, and then divide 1440/.052, giving the same answer of 27,692, choice (C).
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The New SAT
Hello everybody. I have been getting tons of emails lately with one very specific question. Everybody wants to know if I plan to update my books and other materials to reflect the changes being made by the College Board for the revised SAT. And the answer is yes. This has already been done. You can find all of my new SAT prep books on my product page here: SAT Math Prep Books
For those of you that are not aware, the College Board has decided to make major changes to the SAT beginning with the March 2016 test. The first PSAT to administer these changes was in October, 2015 and the first new SAT will be in March, 2016. I spent the last six months doing extensive research on what those changes would be so that I could produce the highest quality material for your SAT math preparation.
I would like to leave you with two SAT math questions in the style of the revised test. Please feel free to post your solutions or attempted solutions in the comments below and we can discuss the best way to solve each of these problems. I will give full solutions next week.
Level 2 Number Theory
- A chemist has a supply of 5.2 liter bottles of a certain solvent that must be shipped to a central warehouse. The warehouse can accept the solvent at the rate of 3 hectoliters per minute for a maximum of 8 hours per day. If 1 hectoliter equals 100 liters, what is the maximum number of bottles that the warehouse could receive from the chemist each day.
(A) 461
(B) 462
(C) 27,692
(D) 83,200
Level 2 Data Analysis
- A puddle with an area of 500 cm2, is monitored by scientists for the number of paramecia present. The scientists are interested in two distinct species, let’s call them “species A” and “species B.” At time t = 0, the scientists measure and estimate the amount of species A and species B present in the puddle. They then proceed to measure and record the number of each species of paramecium present every hour for 12 days. The data for each species, were then fit by a smooth curve, as shown in the graph above. Which of the following is a correct statement about the data above?
(A) At time t = 0, the number of species B present is 150% greater than the number of species A present.
(B) At time t = 0, the number of species A present is 75% less than the number of species B present.
(C) For the first 3 days, the average growth rate of species B is higher than the average growth rate of species A.
(D) The growth rate of both species A and species B decreases for the last 8 days.
If you liked this article, please share it with your Facebook friends:
And don’t forget to check out my social media pages:
555 Geometry Problems
Today I would like to announce the release of 555 Geometry Problems for High School Students.
The paperback is now on sale on Amazon for only $5.27.
This sale will run until approximately 6 PM today, and once the sale ends the price will go up to $34.99. If you want to take advantage of the sale price I strongly recommend you purchase the book before 6 PM.
Click the following link to get to the book’s Amazon page: 555 Geometry Problems
As an additional incentive to purchase this book today, I will also give you an additional book for FREE as a downloadable PDF file. You can choose ANY of my other books. So if you would like a different book, go ahead and purchase this one (as soon as it is available), forward me your Amazon confirmation email and let me know which of my books you would like for free. You will be provided with a link to download your additional free book. This offer is available until the end of today (March 30, 2015).
Take a look at my product page to see all of my books: Get 800 Product Page
I am also making the following promotion available until April 30, 2015: if you buy any 3 of my books in paperback, you get all 6 of the following SAT math prep books for free.
A Trick For Free Two Day Shipping
I would like to finish this post with a little trick you can use to get free 2 day shipping on any of the books you decide to purchase without making any additional purchases. If you have never used Amazon Prime you can sign up for a free month using the following link.
Sign Up For Amazon Prime For Free
If you have already had a free trial of Amazon Prime you can simply open up a new Amazon account to get a new free trial. It just takes a few minutes! You will need to use a different email address than the one you usually use.
This next part is very important! After you finish your transaction, go to your Account, select “Manage my prime membership,” and turn off the recurring billing. This way in a month’s time Amazon will not start charging you for the service.
After shutting off the recurring billing you will still continue to receive the benefit of free 2 day shipping for one month. This means that as long as you use this new Amazon account for your purchases you can do all of your shopping on Amazon for the next month without having to worry about placing minimum orders to get free shipping.
Just be aware that certain products from outside sellers do not always qualify for free shipping, so please always check over your bill carefully before you check out.
Well I hope you decide to take advantage of this very special offer, or at the very least I hope you will benefit from my Amazon “free 2 day shipping trick.” Here is the link one more time:
Sign Up For Amazon Prime For Free
If you think your friends might be interested in this special offer, please share it with them on Facebook:
Thank you all for your continued support!