500 New SAT Math Problems
Just 19.99 on Amazon

Hi everyone! The latest edition of 500 New SAT Math Problems is now available in paperback from Amazon. This edition just has been modified from the previous edition to account for the changes on the Digital SAT.

The paperback is now on sale on Amazon for only $19.99. Note that once the sale ends (by the end of today), the price of this book will go up to $42.99. 

The promotion has ended. Thanks to everyone who participated. The book is now available at its regular price here: 500 New SAT Math Problems

If you have any questions, feel free to contact me at steve@SATPrepGet800.com 

Thank you all for your continued support!

A Trick For Free Two Day Shipping

I would like to finish this post with a little trick you can use to get free 2 day shipping on any of the books you decide to purchase without making any additional purchases. If you have never used Amazon Prime you can sign up for a free month using the following link.

Sign Up For Amazon Prime For Free

If you have already had a free trial of Amazon Prime you can simply open up a new Amazon account to get a new free trial. It just takes a few minutes! You will need to use a different email address than the one you usually use.

This next part is very important! After you finish your transaction, go to your Account, select “Manage my prime membership,” and turn off the recurring billing. This way in a month’s time Amazon will not start charging you for the service.

After shutting off the recurring billing you will still continue to receive the benefit of free 2 day shipping for one month. This means that as long as you use this new Amazon account for your purchases you can do all of your shopping on Amazon for the next month without having to worry about placing minimum orders to get free shipping.

Just be aware that certain products from outside sellers do not always qualify for free shipping, so please always check over your bill carefully before you check out.

Well I hope you decide to take advantage of this very special offer, or at the very least I hope you will benefit from my Amazon “free 2 day shipping trick.” Here is the link one more time:

Sign Up For Amazon Prime For Free

If you think your friends might be interested in this special offer, please share it with them on Facebook:

Thank you all for your continued support!

College Admissions Online Academy

Today I would like to introduce my colleague Ashly Jordan and offer you a discount on her online course. Ashly is a veteran science teacher and the owner of My Education Connections, LLC. Realizing the need to help families and students achieve their dreams of a college education without becoming overwhelmed and frustrated with the associated high costs, in 2016 Ashly began her business to help families save up to 50% on college costs and to develop a personalized plan for college to graduate on time while massively reducing student loan debt.

Ashly is now offering a new online course: College Admissions Mastery. In this course, she will take a really deep dive into how to help you plan and pay for college while developing a personalized plan to graduate on time. She covers getting students into their dream school, funding options, resumes, personal statements, and essays.

The course is normally $125 but by signing up using my discount code the cost will be reduced to $99. The next course starts this Saturday, may, 5th, at 10 a.m. EST.

When you sign up, simply use the code Get800 to get the discounted price. You can enroll here: College Admissions Mastery Course

I hope you will take advantage of this program to help to alleviate the stress of the college admissions process.

Spaces are limited, as she takes on only 15 clients for each course session so that she can give students the individualized attention they deserve.

Don’t forget to use the code Get800 at checkout to get the discounted price!

Please contact me with questions at steve@SATPrepGet800.com

Thank you all for your continued support!

Disclaimer: By using the discount code Get800 at checkout, my company will be receiving a commission on the sale. Ashly gets a new client, you get a wonderful course at a discounted rate, and my company gets a commission. It’s a win-win-win for everyone. 

Tutoring Referral Program

You can now earn extra money for referring students that are in need of math tutoring or want to sign up for a standardized test prep course. I am currently offering a commission of 10% for referrals for one on one tutoring and a commission of 5% – 10% for referrals for any test prep class. For details on this program use the following link: Tutoring Referral Program

Here is an example of how you can earn money through referrals: If you refer a student to me, and that student pays my fee of $250 per session for 5 sessions, then you will be paid $125 for the referral. You will continue to receive commission for as long as I continue working with that student.

As another example, if you refer a student to me and they sign up for a class for $2000, you will receive $100 (5%) once that student completes his or her payment. If you refer a full class of 5 or more students, the class commission will be a full 10% (so, referring me a group of 5 students, each paying my discounted rate of $2000, will earn you a commission of $1000). Note that you cannot receive commission for anyone that is in your immediate family or that lives in your household (an exception is made if you refer a full class of 5 or more).

Payments will be made via PayPal.

You or your referral can email me at steve@SATPrepGet800.com

My Classes and Current Rates

I am currently offering a 50% discount on private tutoring and a small discount on classes. Here is what I have available.

• SAT Full Prep Course – $2000
• SAT Math Prep Course – $1400
• ACT Math Prep Course – $1400
• AP Calculus AB Prep Course – $1400
• AP Calculus BC Prep Course – $1800
• GRE Math Prep Course – $1400
• Private tutoring – $250 per hour

Private tutoring is available for all of the following:

• K-12 mathematics
• all undergraduate math courses
• graduate courses in Mathematical Logic, Set Theory, Real and Complex Analysis, Linear and Abstract Algebra, and Differential Equations
• Standardized Test Prep in SAT, ACT, SAT Math Subject Tests, AP Calculus, GRE, GMAT, Math Regents

My Credentials

Here are some of my credentials:

• PhD in Mathematics
• 20+ years tutoring and teaching experience
• Author of more than 20 books for standardized test prep
• Many students with perfect scores on the SAT, ACT, and AP Calculus exams

My full resume can be viewed here: Dr. Steve Warner’s CV

If you would like to discuss your needs for tutoring further, feel free to email me at steve@SATPrepGet800.COM or call me at 718-980-2935 and leave a message. I can usually get back to you within a few hours.

Thank you all for your continued support!

SAT Level 5 Passport to Advanced Math Problem
with Solution

Today I would like to provide a solution for the difficult Passport to Advanced Math SAT problem I recently posted. Here is the original post: SAT Level 5 PAM Problem

Level 5 Passport to Advanced Math

g(x)=x² + 4x – 1
h(x)=2x³ + 3x² + x

The polynomials g and h are defined above. Which of the following polynomials is divisible by 2x – 1 ?

A) k(x) = g(x) – h(x)
B) k(x) = 12g(x) – h(x)
C) k(x) = g(x) – 10h(x)
D) k(x) = 12g(x) – 10h(x)

First recall that the factor theorem says that p(r) = 0  if and only if x – r is a factor of the polynomial p.

* Solution using the factor theorem: We note that 2x – 1 = 2(x – 1/2), and use r = 1/2. We have

g(1/2) = (1/2)² + 4(1/2) – 1 = 1/4 + 2 – 1 = 1/4 + 1 = 5/4

h(1/2) = 2(1/2)³ + 3(1/2)² + 1/2 = 2(1/8) + 3(1/4) + 1/2 = 1/4 + 3/4 + 1/2 = 3/2

Since 12(5/4) – 10(3/2) = 15 – 15 = 0, we see that if k(x) = 12g(x) – 10h(x), then k(1/2) = 0, and it follows that 2x – 1 is a factor of k. So, the answer is choice D.

Note: To use the factor theorem, we need to divide by a linear polynomial of the form x – r. So, we rewrite 2x – 1 as 2(x – 1/2). We see that 2x – 1 is a factor of the polynomial if and only if x – 1/2  is a factor of the polynomial. So, we use r = 1/2.

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

SAT Level 5 Passport to Advanced Math Problem

Here is a difficult Passport to Advanced Math problem for the SAT. I will provide a solution soon.

Level 5 Passport to Advanced Math

g(x)=x² + 4x – 1
h(x)=2x³ + 3x² + x

The polynomials g and h are defined above. Which of the following polynomials is divisible by 2x – 1 ?

A) k(x) = g(x) – h(x)
B) k(x) = 12g(x) – h(x)
C) k(x) = g(x) – 10h(x)
D) k(x) = 12g(x) – 10h(x)

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

SAT Level 5 Heart of Algebra Problem

Here is a hard Heart of Algebra problem for the SAT. I will provide several different solutions to this problem over the next few days.

Level 5 Heart of Algebra

A worker earns $12 per hour for the first 40 hours he works in any given week, and $18 per hour for each hour above 40 that he works each week. If the worker saves 75% of his earnings each week, what is the least number of hours he must work in a week to save at least $441 for the week?

A) 6
B) 8
C) 46
D) 47

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

SAT Level 5 Heart of Algebra Problem

Here is a hard Heart of Algebra problem for the SAT. I will provide several different solutions to this problem over the next few days.

Level 5 Heart of Algebra

A worker earns $12 per hour for the first 40 hours he works in any given week, and $18 per hour for each hour above 40 that he works each week. If the worker saves 75% of his earnings each week, what is the least number of hours he must work in a week to save at least $441 for the week?

A) 6
B) 8
C) 46
D) 47

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

Hard SAT Geometry Problem with Solution

Today I would like to solve the SAT geometry problem I posted yesterday. You can see the original post here: Hard SAT Geometry Problem

Level 5 Geometry

ABCD shown above is a square, m∠DFE = 60°, EF = 3, and CF = 4. What is the area of square ABCD ?

Solution: DF is the hypotenuse of a 30, 60, 90 triangle (ΔDEF). Since EF = 3, we have DF = 6.

We can now use the Pythagorean Theorem to get

DC² = DF² – CF² = 6² – 4² = 36 – 16 = 20.

Notes: (1) The area of a square is A = s², where s is the length of a side of the square.

(2) There is no need to find DC here because the area of the square is equal to DC², and that’s what we found.

(3) The 30, 60, 90 triangle and the Pythagorean Theorem are both given to you at the beginning of each SAT math section.

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

Hard SAT Geometry Problem

Here is a hard SAT Geometry problem. Come back tomorrow for a solution.

Level 5 Geometry

ABCD shown above is a square, m∠DFE = 60°, EF = 3, and CF = 4. What is the area of square ABCD ?

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

SAT Level 4 Passport to Advanced Math Problem with Solution

Today I would like to solve the last SAT math problem I posted. You can see the original post here: SAT Level 4 Passport to Advanced Math Problem

Level 4 Passport to Advanced Math

Let m = 2x + 7 and k = 2x – 7, and write km = cx² + d, where c and d are constants. What is the value of c – d ?

* Solution using the difference of two squares:

km = (2x + 7)(2x – 7) = 4x² – 49.

So, we have 4x² – 49 = cx² + d.

Thus, c = 4 and d = –49.

It follows that c – d = 4 – (–49) = 4 + 49 = 53.

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.

SAT Level 4 Passport to Advanced Math Problem

Here is a hard Passport to Advanced Math SAT problem. Come back tomorrow for a solution.

Level 4 Passport to Advanced Math

Let m = 2x + 7 and k = 2x – 7, and write km = cx² + d, where c and d are constants. What is the value of c – d ?

Share this problem with your Facebook friends that are preparing for the SAT

If you’re preparing for the SAT, you may want to check out the Get 800 collection of SAT math books.